document.write( "Question 146834: how would i do this? Simplify the following fractions by putting them in lowest terms or by performing the indicated operations\r
\n" ); document.write( "\n" ); document.write( "81-x to the 4th over 3-x divided by 9+x2 over 9 =
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Algebra.Com's Answer #108298 by mangopeeler07(462)\"\" \"About 
You can put this solution on YOUR website!
Start with \"%2881-x%5E4%29%2F%283-x%29\" divided by \"%289%2Bx%5E2%29%2F%289%29\". \r
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\n" ); document.write( "\n" ); document.write( "Find the common denominator, which would be 9(3-x). Manipulate the fractions and get \"%289%2881-x%5E4%29%29%2F9%283-x%29\" divided by \"%28%283-x%29%289%2Bx%5E2%29%29%2F%289%283-x%29%29\". \r
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\n" ); document.write( "\n" ); document.write( "Then eliminate the denominators from the equation. Get \"9%2881-x%5E4%29\" divided by \"%283-x%29%289%2Bx%5E2%29\". \r
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\n" ); document.write( "\n" ); document.write( "Factor all of the expressions. The expression \"81-x%5E4\" factors into \"%289%2Bx%5E2%29%289-x%5E2%29\". Then \"9-x%5E2\" factors to \"%283-x%29%283%2Bx%29\". So the numerator becomes \"9%289%2Bx%5E2%29%283-x%29%283%2Bx%29\" while the denominator remains \"%289%2Bx%5E2%29%283-x%29\". So it looks like: \"%289%289%2Bx%5E2%29%283-x%29%283%2Bx%29%29%2F%28%289%2Bx%5E2%29%283-x%29%29\". \r
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\n" ); document.write( "\n" ); document.write( "Now just cancel out like terms in the numerator and the denominator, which would be \"%283-x%29\" and \"%289%2Bx%5E2%29\". Then you are left with \"%289%283%2Bx%29%29%2F1\". or \"9%283%2Bx%29\". You can stop there if you want to. Going further is not necessary, but if you want to anyway, read on.\r
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\n" ); document.write( "\n" ); document.write( "It is very easy from here. Just distribute the 9 to both terms and get \"%2827%2B9x%29%2F1\" or simply \"27%2B9x\".
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