document.write( "Question 147915: Graph the equations given below using the indicated method\r
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document.write( "x = -3\r
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document.write( "y = 2 \n" );
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Algebra.Com's Answer #108288 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! x = -3\r \n" ); document.write( "\n" ); document.write( "y = 2 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These basically translate into x = -3 when y is whatever, or (-3,whatever) and \n" ); document.write( "y = 2 when x is whatever, or (whatever,2). So you would graph each line normally. Let's do x=-3 first. All you have to do is make sure x=-3. Y can be any old thing. Let's see what it would look like: \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "See? Y can be anything as long as x=-3 is true.\r \n" ); document.write( "\n" ); document.write( "Now let's do y=2. Again, same concept. As long as y=2, x can be any old thing. Let's see what it would look like: \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This time x can be anything as long as y=2 is true.\r \n" ); document.write( "\n" ); document.write( "**Rule of thumb, if an equation is simply x=something or y=something, the line will just mirror the opposite axis, while running through the indicated point on the corresponding axis. In other words, the line x=-3 mirrors the y axis and runs through the given point -3 on the x axis, and the line y=2 mirrors the x axis and runs through the given point 2 on the y-axis. The graphs illustrate that nicely. \n" ); document.write( " |