document.write( "Question 147899: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. Hint: You did this in Module 3 Assignment 8. Now you have to write the equation and solve it.\r
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Algebra.Com's Answer #108281 by Fombitz(32388)\"\" \"About 
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The length of a rectangle is 3 more than twice its width.
\n" ); document.write( "1.\"L=3%2B2W\"
\n" ); document.write( "The perimeter is 48 feet.
\n" ); document.write( "\"P=48\"
\n" ); document.write( "In terms of length and width, the perimeter of a rectangle is,
\n" ); document.write( "\"P=2L%2B2W\"
\n" ); document.write( "2.\"2L%2B2W=48\"
\n" ); document.write( "Use eq. 1 and substitute into eq. 2 for L,
\n" ); document.write( "2.\"2L%2B2W=48\"
\n" ); document.write( "\"2%283%2B2W%29%2B2W=48\"
\n" ); document.write( "\"6%2B4W%2B2W=48\"
\n" ); document.write( "\"6%2B6W=48\"
\n" ); document.write( "\"6W=42\"
\n" ); document.write( "\"W=7\"
\n" ); document.write( "Now use eq. 1 to solve for L.
\n" ); document.write( "1.\"L=3%2B2W\"
\n" ); document.write( "\"L=3%2B2%287%29\"
\n" ); document.write( "\"L=3%2B14\"
\n" ); document.write( "\"L=17\"\r
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