document.write( "Question 147814: Suppose that the function P=12+50ln x represents the percentage of inbound e-mail in the U.S. that is considered spam, where x is the number of years after 2001.\r
\n" ); document.write( "\n" ); document.write( "Carry all calculations to six decimals on each intermediate step when necessary.
\n" ); document.write( "a) use this model to approximate the percentage of spam in the year 2005. I need to know all steps please.\r
\n" ); document.write( "\n" ); document.write( "b) Use this model to determine how many years it will take (to two decimal places) for the percent of spam to reach 90% provided that the law enforcement regarding spammers does not change.
\n" ); document.write( "My answer fo first part is P=12+3.91(4) = P=12+15.65 P= 27.65% Is this correct and the second part 90=12+50ln(x), 90=12+3.91(x), 90=15.91x, 15.91years Is this correct? Thanks for help
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Algebra.Com's Answer #108270 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Your thinking is correct.
\n" ); document.write( "However your calculations are not.
\n" ); document.write( "\"P=12%2B50%2Aln%28x%29\"
\n" ); document.write( "\"P=12%2B50%2Aln%284%29\"
\n" ); document.write( "\"P=12%2B50%2A1.386294\"
\n" ); document.write( "I'm not sure where the 3.91 comes in other than from ln(50)=3.91.
\n" ); document.write( "That's your mistake.
\n" ); document.write( "\"P=12%2B50%2A1.386294\"
\n" ); document.write( "\"P=12%2B69.31\"
\n" ); document.write( "\"P=81.31\"
\n" ); document.write( "And the same for the second part.
\n" ); document.write( "The thinking was clear but the calculation had mistakes.
\n" ); document.write( "\"90=12%2B50%2Aln%28x%29\"
\n" ); document.write( "Solve for x.
\n" ); document.write( "\"78=50%2Aln%28x%29\" Subtract 12 from both sides.
\n" ); document.write( "\"1.56=ln%28x%29\" Divide both side by 50.
\n" ); document.write( "\"x=4.76\" Use the inverse of the natural log function (\"e%5Ex\").
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