document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147884>Question 147884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 11/x > 12 find x? how to do this the symbol '>' implies that 'more than'... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108257 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simply solve for 'x' as though the \"greater than\" sign (>) was an \"equal sign\".  But, remember to \"flip\" the sign ONLY if you multiply or divide by a negative number.<BR>\n" );
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document.write( "11/x > 12<BR>\n" );
document.write( "multiplying both side by 'x':<BR>\n" );
document.write( "11 > 12x<BR>\n" );
document.write( "dividing both sides by 12:<BR>\n" );
document.write( "11/12 > x<BR>\n" );
document.write( ".<BR>\n" );
document.write( "solution: x is \"less than\" 11/12<BR>\n" );
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