document.write( "Question 147886: four times the smallest of three consecutive odd intergers is five more than three times the largest.what is the sum of these consecutive odd intergers? \n" ); document.write( "
Algebra.Com's Answer #108256 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Let x = 1st consecutive odd integer \n" ); document.write( "x+2 = 2nd odd integer \n" ); document.write( "x+4 = 3rd odd integer \n" ); document.write( ". \n" ); document.write( "from: \n" ); document.write( "\"four times the smallest of three consecutive odd intergers is five more than three times the largest\" \n" ); document.write( "we get: \n" ); document.write( "4x = 3(x+4)+5 \n" ); document.write( ". \n" ); document.write( "solving for x: \n" ); document.write( "4x = 3(x+4)+5 \n" ); document.write( "4x = 3x+12+5 \n" ); document.write( "4x = 3x+17 \n" ); document.write( "x = 17 (1st odd integer) \n" ); document.write( ". \n" ); document.write( "then \n" ); document.write( "x+2 = 19 (2nd odd integer) \n" ); document.write( "x+4 = 21 (3rd odd integer) \n" ); document.write( ". \n" ); document.write( "solution: 17+19+21=57\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |