document.write( "Question 147886: four times the smallest of three consecutive odd intergers is five more than three times the largest.what is the sum of these consecutive odd intergers? \n" ); document.write( "
Algebra.Com's Answer #108256 by nerdybill(7384)\"\" \"About 
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Let x = 1st consecutive odd integer
\n" ); document.write( "x+2 = 2nd odd integer
\n" ); document.write( "x+4 = 3rd odd integer
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\n" ); document.write( "from:
\n" ); document.write( "\"four times the smallest of three consecutive odd intergers is five more than three times the largest\"
\n" ); document.write( "we get:
\n" ); document.write( "4x = 3(x+4)+5
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\n" ); document.write( "solving for x:
\n" ); document.write( "4x = 3(x+4)+5
\n" ); document.write( "4x = 3x+12+5
\n" ); document.write( "4x = 3x+17
\n" ); document.write( "x = 17 (1st odd integer)
\n" ); document.write( ".
\n" ); document.write( "then
\n" ); document.write( "x+2 = 19 (2nd odd integer)
\n" ); document.write( "x+4 = 21 (3rd odd integer)
\n" ); document.write( ".
\n" ); document.write( "solution: 17+19+21=57\r
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