document.write( "Question 147808: My question is: Write the equation for the ellipse whose center is the origin, has a horizontal major axis length of 12 and passses through the point (-4,2).
\n" ); document.write( "I need help with this, since the horizontal axis is at the origin I get that the foci is (-6,0) and (6,0). I find that the equation will be \"%28x%5E2%2F36%29%2B%28y%5E2%2Fb%5E2%29=1\" but I am having trouble finding what \"b%5E2\" equals. Can you help me?
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Algebra.Com's Answer #108202 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
substituting the coordinates of the point __ (16/36)+(4/(b^2))=1\r
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\n" ); document.write( "\n" ); document.write( "subtracting 16/36 __ 4/(b^2)=20/36 __ \"cross\" multiplying __ 144=20b^2\r
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\n" ); document.write( "\n" ); document.write( "dividing by 20 __ 36/5=b^2
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