document.write( "Question 147818: soybean meal is 14% protein; cornmeal is 7% protein.how many pounds of each should be mixed together in order to get 280lb mixture that is 12% protein?
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document.write( "how many pounds of cornmeal should be in the mixture?
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document.write( "how many pounds of soybean meal should be in the mixture? \n" );
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Algebra.Com's Answer #108201 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! soybean meal is 14% protein; cornmeal is 7% protein.how many pounds of each \n" ); document.write( " should be mixed together in order to get 280lb mixture that is 12% protein? \n" ); document.write( ": \n" ); document.write( "how many pounds of cornmeal should be in the mixture? \n" ); document.write( ": \n" ); document.write( "Let x = amt of cornmeal required (7% protein): \n" ); document.write( ": \n" ); document.write( "how many pounds of soybean meal should be in the mixture? \n" ); document.write( ": \n" ); document.write( "(280-x) = amt of soymeal (14% protein) required \n" ); document.write( ": \n" ); document.write( "amt of protein equation: \n" ); document.write( ".07x + .14(280-x) = .12(280) \n" ); document.write( ": \n" ); document.write( ".07x + 39.2 - .14x = 33.6 \n" ); document.write( ": \n" ); document.write( ".07x - .14x = 33.6 - 39.2 \n" ); document.write( "; \n" ); document.write( "-.07x = -5.6 \n" ); document.write( "x = \n" ); document.write( "x = +80 lb of cornmeal required \n" ); document.write( ": \n" ); document.write( "280 - 80 = 200 lb of soymeal \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution: \n" ); document.write( ".07(80) + .14(200) = .12(280) \n" ); document.write( "5.6 + 28 = 33.6; confirms our solutions \n" ); document.write( " \n" ); document.write( " |