document.write( "Question 147753This question is from textbook
\n" ); document.write( ": use the echelon method to solve.\r
\n" ); document.write( "\n" ); document.write( "x + y/3 = -6\r
\n" ); document.write( "\n" ); document.write( "x/5 + y/4 = -7/4
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Algebra.Com's Answer #108189 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1.\"x%2By%2F3=-6\"
\n" ); document.write( "2.\"x%2F5%2By%2F4=-7%2F4\"
\n" ); document.write( "or in matrix form,
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\n" ); document.write( "Multiply eq. 1 by (-1/5) and add to eq. 2, to remove x.
\n" ); document.write( "\"%28-1%2F5%29x-y%2F15=6%2F5\"
\n" ); document.write( "\"x%2F5%2By%2F4=-7%2F4\"
\n" ); document.write( "2'.\"%28-1%2F15%2B1%2F4%29y=6%2F5-7%2F4\"
\n" ); document.write( "2'.\"%2811%2F60%29y=-11%2F20\"
\n" ); document.write( "Now your two equations, in echelon form, are
\n" ); document.write( "1.\"x%2By%2F3=-6\"
\n" ); document.write( "2'.\"0x%2B%2811%2F60%29y=-11%2F20\"
\n" ); document.write( "or in matrix form,
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\n" ); document.write( "\n" ); document.write( "You can solve for y from 2'.
\n" ); document.write( "2'.\"%2811%2F60%29y=-11%2F20\"
\n" ); document.write( "\"y=-%2811%2F20%29%2860%2F11%29\"
\n" ); document.write( "\"y=-3\"
\n" ); document.write( "From 1,
\n" ); document.write( "1.\"x%2By%2F3=-6\"
\n" ); document.write( "\"x=-6%2B3%2F3\"
\n" ); document.write( "\"x=-6%2B1\"
\n" ); document.write( "\"x=-5\"
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