document.write( "Question 147547: Let f(x) = -x^3 + 3x^2 - 3x + 1, and g(x) be f(x) divided by 1 - x; solve for g(x) if 1 - x is a factor of f(x).
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document.write( "a. g(x) = x^4 - 4x^3 + 6x^2 - 4x + 1
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document.write( "b. g(x) = x^3 - 3x^2 + 3x - 1
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document.write( "c. g(x) = -x^2 + 2x - 1
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document.write( "d. g(x) = x^2 - 2x + 1 \n" );
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Algebra.Com's Answer #108176 by nabla(475)![]() ![]() ![]() You can put this solution on YOUR website! We shall want \n" ); document.write( "g(x)=(-x^3 + 3x^2 - 3x + 1)/(-x+1)\r \n" ); document.write( "\n" ); document.write( "You can solve this a few different ways. I will use long division. \n" ); document.write( "......x^2-2x+1 \n" ); document.write( "_______________________ \n" ); document.write( "-x+1)-x^3 + 3x^2 - 3x + 1 \n" ); document.write( "...-(-x^3+x^2) \n" ); document.write( "________________ \n" ); document.write( "........2x^2-3x \n" ); document.write( "......-(2x^2-2x) \n" ); document.write( "__________________ \n" ); document.write( "..........-x+1 \n" ); document.write( "........-(-x+1) \n" ); document.write( "_________________ \n" ); document.write( ".............0\r \n" ); document.write( "\n" ); document.write( "So g(x)=x^2-2x+1 \n" ); document.write( " |