document.write( "Question 22298: Find x: log3 5 = log3 x − log3 4 \n" ); document.write( "
Algebra.Com's Answer #10815 by AnlytcPhil(1806)\"\" \"About 
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document.write( "(1)   logBA + logBC = logB(AC)\r\n" );
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document.write( "(2)   If logBA = logBC then A = C, if B > 0 and B ¹ 1\r\n" );
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document.write( "log35 = log3x − log34\r\n" );
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document.write( "Add log34 to both sides to get as many terms positive as possible\r\n" );
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document.write( "log35 + log34 = log3x\r\n" );
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document.write( "Use (1)\r\n" );
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document.write( "log3(5·4) = log3x\r\n" );
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document.write( "Rewrite 5·4 as 20\r\n" );
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document.write( "log320 = log3x  \r\n" );
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document.write( "Use (2):\r\n" );
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document.write( "20 = x\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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