document.write( "Question 147776: find three consecutive multiples of 5 such that the sum of the squares of the first two is 125 greater than the square of the third. \n" ); document.write( "
Algebra.Com's Answer #108149 by stanbon(75887)\"\" \"About 
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find three consecutive multiples of 5 such that the sum of the squares of the first two is 125 greater than the square of the third.
\n" ); document.write( "----------
\n" ); document.write( "1st: 5x
\n" ); document.write( "2nd: 5x+5
\n" ); document.write( "3rd: 5x+10
\n" ); document.write( "---------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "(5x)^2 + (5x+5)^2 = (5x+10)^2 + 125
\n" ); document.write( "25x^2 + 25x^2 + 50x + 25 = 25x^2 + 100x + 100 + 125
\n" ); document.write( "x^2 + x^2 + 2x + 1 = x^2 + 4x + 4 + 5
\n" ); document.write( "x^2 -2x -8 = 0
\n" ); document.write( "(x-4)(x+2) = 0
\n" ); document.write( "x = 4 or x = -2
\n" ); document.write( "-----------------
\n" ); document.write( "If x = 4:
\n" ); document.write( "1st = 20
\n" ); document.write( "2nd = 25
\n" ); document.write( "3rd = 30
\n" ); document.write( "Checking: 20^2 + 25^2 = 30^2+125
\n" ); document.write( "400 + 625 = 900 + 125
\n" ); document.write( "1025 = 1025
\n" ); document.write( "-------------
\n" ); document.write( "If x = -2:
\n" ); document.write( "1st = -10
\n" ); document.write( "2nd = -5
\n" ); document.write( "3rd = 0
\n" ); document.write( "Checking:
\n" ); document.write( "(-10)^2 + (-5)^2 = 0^2 + 125
\n" ); document.write( "100 + 25 = 125
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "=========== \n" ); document.write( "
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