document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147773>Question 147773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log5 (to the power of 5) (x+3)+log5(big 4)=log5(big 36)\r<BR>\n" );
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document.write( "once again its:\r<BR>\n" );
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document.write( "log5(x+3)+log5 4= log5 36 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108141 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> All logs are the same base, 5. The sum of logs on the left side means the 2 terms are multiplied.  That is, the sum of 2 logs is the log of the product of the 2 terms.<BR>\n" );
document.write( "So, log(x+3) + log(4) = log(36)  (Regardless of base as long as they match)<BR>\n" );
document.write( "log[(x+3)*4] = log(36)<BR>\n" );
document.write( "If the logs are equal, the terms are equal.<BR>\n" );
document.write( "(x+3)*4 = 36<BR>\n" );
document.write( "4x+12 = 36<BR>\n" );
document.write( "4x = 24<BR>\n" );
document.write( "x = 6<BR>\n" );
document.write( "Check: (6+3)*4 = 36. </SPAN>\n" );
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