document.write( "Question 22286: please help me siplifyig\"1%2F1%2B1%2Fxab+%2B+1%2F1%2B1%2Fxba\" \n" ); document.write( "
Algebra.Com's Answer #10812 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Simplify:
\n" ); document.write( "\"1%2F1+%2B+1%2Fxab+%2B+1%2F1+%2B+1%2Fxba\" First, \"1%2F1+=+1\" and \"1%2B1+=+2\"
\n" ); document.write( "\"2+%2B+1%2Fxab+%2B+1%2Fxba\" Now, \"1%2Fxab+=+1%2Fxba\" and \"1%2Fxab+%2B+1%2Fxab+=+2%2Fxab\"
\n" ); document.write( "\"2+%2B+2%2Fxab\" Now add the two fractions, common denominator is xab.
\n" ); document.write( "\"2+%2B+2%2Fxab+=+%282xab+%2B+2%29%2Fxab\" = \"2%28xab+%2B+1%29%2Fxab\"
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