document.write( "Question 2545: David has 40 coins in his bank. If the coins consists of quarters and dimes and value $7.60, how many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #1081 by kiru_khandelwal(79)![]() ![]() ![]() You can put this solution on YOUR website! Let the \n" ); document.write( "number of quarters = x \n" ); document.write( "number of dimes = y\r \n" ); document.write( "\n" ); document.write( "Since david has 40 coins, so \n" ); document.write( "x+y = 40 ...........Equation (1)\r \n" ); document.write( "\n" ); document.write( "1 quarter = 25 cents...so x quarters = 25*x cents \n" ); document.write( "1 dime = 10 cents.....so y dimes = 10*y cents \n" ); document.write( "$7.60 = 7.60 * 100 = 760 cents\r \n" ); document.write( "\n" ); document.write( "Since the total value is $7.60 or 760 cents \n" ); document.write( "Therefore, \n" ); document.write( "25x+10y = 760.........Equation (2)\r \n" ); document.write( "\n" ); document.write( "Solving equation (2) \n" ); document.write( "5*5x + 5*2y = 5*152 \n" ); document.write( "=> 5(5x+2y) = 5(152) \n" ); document.write( "=> 5x+2y=152.........Equation (3)\r \n" ); document.write( "\n" ); document.write( "From Equation(1) \n" ); document.write( "y = 40-x\r \n" ); document.write( "\n" ); document.write( "Substituting the value of y in Equation(3) \n" ); document.write( "5x + 2y = 152 \n" ); document.write( "=> 5x + 2(40-x) = 152 \n" ); document.write( "=> 5x + 80 - 2x = 152 \n" ); document.write( "=> 3x = 152-80 \n" ); document.write( "=> 3x = 72 \n" ); document.write( "=> x = 24 \n" ); document.write( "Therefore, No. of Quarters = 24\r \n" ); document.write( "\n" ); document.write( "As, y = 40 -x \n" ); document.write( "=> y = 40-24 = 16 \n" ); document.write( "Number of dimes = 16\r \n" ); document.write( "\n" ); document.write( "Hence solved \n" ); document.write( " |