document.write( "Question 147711: I need help!
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document.write( "1. write the equation of a line whose slope is -2 and passes through (-1,6). Write answer in slope-intercept form.\r
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document.write( "2. Solve for x: (2x-7)(x+4)=0\r
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document.write( "3. find the vertex of f(x)=3x^2-6x+8\r
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document.write( "4. find the y-intercept of the cubic f(x)=(x-2)(x+1)(x-3) \n" );
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Algebra.Com's Answer #108096 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! 1. y=mx+b where m is the slope and b is the y-intercept (what y is when x is zero). So y=-2x+b. To find b, you know that the slope is rise/run or -2/1. So take the point (-1,6) and add 1 to x and subtract 2 from y. You get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. (2x-7)(x+4)=0. Just take each expression separately and set each one equal to zero. what minus seven equals zero? Seven. So you know 2x=7. So x there is 7/2. What plus four equals zero? x=-4 there. So the solutions for this equation are x=7/2;-4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3.find the vertex of f(x)=3x^2-6x+8. vertex: the value of y that does not repeat. To get this, plug in a few consecutive values of x and see which one does not repeat an answer. That would be the vertex. In this case, I will let you know that it is at (1,5). Because: \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5 is the only y value that does not repeat.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4. find the y-intercept of the cubic f(x)=(x-2)(x+1)(x-3). y=f(x), so that means find f(0), because the y-intercept is what y is when x is 0. So plug in 0 and get |