document.write( "Question 147690: A grocer mixed peanuts(whose price is 90 cents per kilogram)with almonds(whose price is $1.10 per kilogram)to make a 20-kilogram mixture of nuts for sale at 98 cents per kilogram. How many kilograms of peanuts and how many kilograms of almonds are in the mixture? \n" ); document.write( "
Algebra.Com's Answer #108076 by mangopeeler07(462)\"\" \"About 
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With two variables------x=number of kilograms of 90cent peanuts and y=number of kilograms of 110cent almonds.\r
\n" ); document.write( "\n" ); document.write( "Set up an equation using the word problem: \"90x%2B110y=98%2820%29\" because the coefficients are the prices of the almonds and peanuts and the variable and 20 are the number of them. Then set up another equation \"x%2By=20\" because the sum of the kilograms is 20. Then solve for x and get \"x=20-y\". Plug that in the first equation and get \"90%2820-y%29%2B110y=98%2820%29\". Then distribute and get \"1800-90y%2B110y=1960\". Combine like terms and get \"1800%2B20y=1960\". Subtract 1800 from both sides and get \"20y=160\". Divide both sides by 20 and get \"y=8\". Then plug 8 in for y in the second equation and get \"x%2B8=20\". So x=12. So 8 kilograms of 110cent almonds and 12 kilograms of 90 cent peanuts is your final answer.\r
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\n" ); document.write( "\n" ); document.write( "With one variable------x=number of kilograms of 90cent peanuts and 20-x=number of kilograms of 110cent almonds.\"90x%2B110%2820-x%29=98%2820%29\"
\n" ); document.write( "Distribute and get \"90x%2B2200-110x=1960\". Then combine like terms and get \"2200-20x=1960\". Subtract 2200 from each side and get \"-20x=-240\". Divide both sides by 20 and get \"x=12\". This is the number of kilograms of 90 cents peanuts. Then do 20-x or 20-12 and get 8. This is the number of kilograms of 110cent almonds. So 8 kilograms of 110cent almonds and 12 kilograms of 90 cent peanuts is your final answer.
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