document.write( "Question 147691: If log 2 ≈ 0.301 and log 3 ≈ 0.477, then log 6 ≈
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document.write( "a. 0.778
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document.write( "b. 0.144
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document.write( "c. 0.176
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document.write( "d. Cannot be determined given this information
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document.write( "
Algebra.Com's Answer #108074 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If log 2 ≈ 0.301 and log 3 ≈ 0.477, then log 6 ≈ \n" ); document.write( "a. 0.778 \n" ); document.write( "b. 0.144 \n" ); document.write( "c. 0.176 \n" ); document.write( "d. Cannot be determined given this information \n" ); document.write( "---------- \n" ); document.write( "log 6 = log2 + log3 \n" ); document.write( "= 0.301 + 0.477 \n" ); document.write( "= 0.778 \n" ); document.write( "----------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |