document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147693>Question 147693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are 20 kilograms of a solution that is 10% salt. How many kilograms of salt must be added to make a solution that is 25% salt? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108070 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  There are 20 kilograms of a solution that is 10% salt. How many kilograms of salt must be added to make a solution that is 25% salt?<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "salt + salt = salt<BR>\n" );
document.write( "Let x be the amount of pure salt that must be added.<BR>\n" );
document.write( "0.10(20) + x = 0.25(20+x)<BR>\n" );
document.write( "2 + x = 5 + (1/4)x<BR>\n" );
document.write( "(3/4)x = 3<BR>\n" );
document.write( "x = 4 kg (amt. of pure salt that must be added.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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