document.write( "Question 147701: Can I have some help me with this problem?\r
\n" ); document.write( "\n" ); document.write( "Single Women - The precentage of women in the 20-24 age group who have never married went from 55% in 1970 to 73% in 2000 (Census Bureau, www.census.gov). Let 1970 be year 0 and 2000 by year 30.\r
\n" ); document.write( "\n" ); document.write( "a) Find and interpret the slope of the line through the points (0,55) and (30,73).
\n" ); document.write( "b) Find the equation of the line in the (a).
\n" ); document.write( "c) What is the meaning of the y-intercept?
\n" ); document.write( "d) Use the equation to predict the percentage in 2010.
\n" ); document.write( "e) If this trend continues, then in what year will the percentage of women in the 20-24 age group who have never married reach 100%
\n" ); document.write( "

Algebra.Com's Answer #108066 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Single Women - The precentage of women in the 20-24 age group who have never married went from 55% in 1970 to 73% in 2000 (Census Bureau, www.census.gov). Let 1970 be year 0 and 2000 by year 30.
\n" ); document.write( "a) Find and interpret the slope of the line through the points (0,55) and (30,73).
\n" ); document.write( "slope = (73-55)/(30-0) = 18/30 = 3/5
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\n" ); document.write( "b) Find the equation of the line in (a).
\n" ); document.write( "y = (3/5)x + 55
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\n" ); document.write( "c) What is the meaning of the y-intercept?
\n" ); document.write( "The percent of women who did not marry in 1970 was 55%
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\n" ); document.write( "d) Use the equation to predict the percentage in 2010.
\n" ); document.write( "f(40) = (3/5)40 + 55 = 24+55 = 79%
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\n" ); document.write( "e) If this trend continues, then in what year will the percentage of women in the 20-24 age group who have never married reach 100%
\n" ); document.write( "100 = (3/5)x + 55
\n" ); document.write( "45 = (3/5)x
\n" ); document.write( "x = 75
\n" ); document.write( "1970 + 75 years = the year 2045
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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