document.write( "Question 147689This question is from textbook
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document.write( ": solve using elimination method and check
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document.write( "15x+3y=-12
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document.write( "2x+y=8 \r
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Algebra.Com's Answer #108055 by GKelly(4)![]() ![]() ![]() You can put this solution on YOUR website! For elimination do the following:\r \n" ); document.write( "\n" ); document.write( "Rewrite the first equation 15x + 3y = -12. Below that multiply -3 times the entire second equation to arrive at -6x - 3y = -24. When you line them up you will be able to cancel out the 3y and solve for x.\r \n" ); document.write( "\n" ); document.write( "15x + 3y = -12 \n" ); document.write( "-6x - 3y = -24 Now cancel out the 3y and solve for x\r \n" ); document.write( "\n" ); document.write( "You'll end up with 9x = -36, x = -4\r \n" ); document.write( "\n" ); document.write( "Now plug -4 into the x value in the first equation and solve for y. \r \n" ); document.write( "\n" ); document.write( "15(-4) + 3y = -12, -60 + 3y = -12, 3y = -12 + 60, 3y = 48, y = 16.\r \n" ); document.write( "\n" ); document.write( "Take the first equation and where x is you plug in -4 and where y is you plug in 16. \r \n" ); document.write( "\n" ); document.write( "15(-4) + 3(16) = -12 \n" ); document.write( "-60 + 48 = -12 \n" ); document.write( "-12 = -12\r \n" ); document.write( "\n" ); document.write( "You're done! \n" ); document.write( " \n" ); document.write( " |