document.write( "Question 147686: Christi's mother gave her $9.00 to buy 10 cent and 15 cent stamps. Christi returned with $1.75 in change and a total of 60 stamps. How many of each kind of stamp did she buy? \n" ); document.write( "
Algebra.Com's Answer #108051 by mangopeeler07(462)\"\" \"About 
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-----With two variables: # of 10 cent stamps is x. # of 15 cent stamps is y. You have the prices of the stamps and the sum of the price of 60 stamps. So first set up an equation \"x%2By=60\". Then set up \"10x%2B15y=725\". Then in the first equation solve for x. You should get \"x=60-y\". Plug that in the second equation and get \"10%2860-y%29%2B15y=725\". Distribute the ten and get \"600-10y%2B15y=725\". Combine like terms \"600%2B5y=725\". Subtract 600 from both sides and get \"5y=125\". Then divide by five and \"y=25\". Then plug in y in the original equation and get \"x=35\". So she bought 35 10cent stamps and 25 15 cent stamps.\r
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\n" ); document.write( "\n" ); document.write( "-----With one variable: Also, you could start out with \"10x%2B15%2860-x%29=725\" since you know the sum to be 60. Then distribute and get \"10x%2B900-15x=725\". Combine like terms and get \"-5x%2B900=725\". Subtract 900 from each side and get \"-5x=175\". Divide by -5 and get x=-35. Now, you can't buy a negative amount of stamps, so make 35 positive. \"x=35\". Then plug x into the original equation and get \"y=25\". So she bought 35 10cent stamps and 25 15 cent stamps.
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