document.write( "Question 147665: 1/2√8-1/3√27+4√50 \n" ); document.write( "

Algebra.Com's Answer #108049 by mangopeeler07(462) $\"\"$ $\"About$

You can put this solution on YOUR website!
1/2√8-1/3√27+4√50\r
\n" ); document.write( "\n" ); document.write( "To fine the square root of a number, find two factors of it, one of which is a perfect square. Perferably the highest perfect square that is a factor of the number. So the square root of 8 would be $\"sqrt%284%29%2Asqrt%282%29\"$ . You can simplify that two $\"2sqrt%282%29\"$ , since the square root of four is two. So substitute that and get $\"1%2F2%282sqrt%282%29%29-1%2F3%28sqrt%2827%29%29%2B4%28sqrt%2850%29%29\"$ . Then find the square root of 27. You should get $\"3sqrt%283%29\"$ . Then get the square root of 50. You should get $\"5sqrt%282%29\"$ . Then plug these in to the original equation. $\"1%2F2%282sqrt%282%29%29-1%2F3%283sqrt%283%29%29%2B4%285sqrt%282%29%29\"$ . Then multiply everything and get $\"sqrt%282%29-sqrt%283%29%2B20sqrt%282%29\"$ . Combine like terms and get $\"21%28sqrt%282%29%29-sqrt%283%29\"$ . \n" ); document.write( "

\n" );