document.write( "Question 147677: Simplify \"sqrt%2849%2Ax%5E12%2Ay%5E4%2Az%5E8%29\" \n" ); document.write( "
Algebra.Com's Answer #108043 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"sqrt%2849%2Ax%5E12%2Ay%5E4%2Az%5E8%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%287%29%5E2%2Ax%5E12%2Ay%5E4%2Az%5E8%29\" Rewrite \"49\" as \"%287%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%287%29%5E2%2A%28x%5E6%29%5E2%2Ay%5E4%2Az%5E8%29\" Rewrite \"x%5E12\" as \"%28x%5E6%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%287%29%5E2%2A%28x%5E6%29%5E2%2A%28y%5E2%29%5E2%2Az%5E8%29\" Rewrite \"y%5E4\" as \"%28y%5E2%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%287%29%5E2%2A%28x%5E6%29%5E2%2A%28y%5E2%29%5E2%2A%28z%5E4%29%5E2%29\" Rewrite \"z%5E8\" as \"%28z%5E4%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( " Break up the square root using the identity \"sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"7%2Ax%5E6%2Ay%5E2%2Az%5E4\" Evaluate each square root. Notice how the squares and the square roots cancel out and we're left with the terms that are in the parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%2849%2Ax%5E12%2Ay%5E4%2Az%5E8%29\" simplifies to \"7%2Ax%5E6%2Ay%5E2%2Az%5E4\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%2849%2Ax%5E12%2Ay%5E4%2Az%5E8%29=7%2Ax%5E6%2Ay%5E2%2Az%5E4\" where every variable is positive.
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