document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147637>Question 147637</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rope 82cm long is cut into two pieces with one peice 4 more than twice as long as the other. find the length of each piece. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108012 by </B><A HREF=/tutors/aboutme.mpl?userid=24HoursTutor.com><B>24HoursTutor.com(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=24HoursTutor.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first piece of rope be x<BR>\n" );
document.write( "The second piece of rope is then 4 + 2x<BR>\n" );
document.write( "We know that together they were 82 cm. So we can write the equations as:<BR>\n" );
document.write( "x+2x+4=82<BR>\n" );
document.write( "3x+4=82<BR>\n" );
document.write( "3x=82-4<BR>\n" );
document.write( "3x=78<BR>\n" );
document.write( "x=78/3<BR>\n" );
document.write( "x=26, the length of the first piece of rope<BR>\n" );
document.write( "4+2x=4+52=56, the length of the second piece of rope.\r<BR>\n" );
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document.write( "Ans.: The length of the two pieces of rope are 26cm and 56 cm.\r<BR>\n" );
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