document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147579>Question 147579</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an amount of $5000 is put into three investments at rates 6%, 7%, and %8 per annum, respectively. The total annual income is $358. The income from the first two investments is $70 more than the income from the third investment. Find the amount of each investment. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107995 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n amount of $5000 is put into three investments at rates 6%, 7%, and %8 per annum, respectively. The total annual income is $358. The income from the first two investments is $70 more than the income from the third investment. Find the amount of each investment<BR>\n" );
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document.write( "Let x = 6% amt (1st investment)<BR>\n" );
document.write( "Let y = 7% amt (2nd investment)<BR>\n" );
document.write( "Let z = 8% amt (3rd investment)<BR>\n" );
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document.write( "The total invested equation:<BR>\n" );
document.write( "x + y + z = 5000<BR>\n" );
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document.write( "The total annual income equation:<BR>\n" );
document.write( ".06x + .07y + .08z = 358<BR>\n" );
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document.write( "It says,\"The income from the first two investments is $70 more than the income from the third investment.\" equation for this:<BR>\n" );
document.write( ".06x + .07y = .08z + 70<BR>\n" );
document.write( ".06x + .07y - .08z = 70<BR>\n" );
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document.write( "Use elimination by subtracting the above equation from the total income equation<BR>\n" );
document.write( ".06x + .07y + .08z = 358<BR>\n" );
document.write( ".06x + .07y - .08z = 70<BR>\n" );
document.write( "------------------------- subtraction eliminates x and y<BR>\n" );
document.write( "0x + 0y + .16z = 268<BR>\n" );
document.write( "z = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=288%2F.16 ALIGN=MIDDLE  ALT=\"288%2F.16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "z = $1800 invested at 8%<BR>\n" );
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document.write( "Using the total equation; z = 1800<BR>\n" );
document.write( "x + y + 1800 = 5000<BR>\n" );
document.write( "x + y = 5000 - 1800<BR>\n" );
document.write( "x + y = 3200<BR>\n" );
document.write( "y = (3200-x); use for substitution<BR>\n" );
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document.write( "Using the total income equation: z = 1800<BR>\n" );
document.write( ".06x + .07y + .08(1800)<BR>\n" );
document.write( ".06x + .07y + 144 = 358<BR>\n" );
document.write( ".06x + .07y = 358 - 144<BR>\n" );
document.write( ".06x + .07y = 214<BR>\n" );
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document.write( "Substitute (3200-x) for y, find x<BR>\n" );
document.write( ".06x + .07(3200-x) = 214<BR>\n" );
document.write( ".06x + 224 - .07x = 214<BR>\n" );
document.write( ".06x -.07x = 214 - 224<BR>\n" );
document.write( "-.01x = -10<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-10%29%2F%28-.01%29 ALIGN=MIDDLE  ALT=\"%28-10%29%2F%28-.01%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = $1000 amt invested at 6%<BR>\n" );
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document.write( "I'll let you find y, the 7% investment<BR>\n" );
document.write( " </SPAN>\n" );
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