document.write( "Question 147618: eighty liters of a 40% antifreeze solution had to be strengthened so it contained 52% antifreeze. how much should be added? \n" ); document.write( "
Algebra.Com's Answer #107990 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
I'm guessing you are adding 100% or pure antifreeze.
\n" ); document.write( "( 80 * 40% + x * 100% ) / ( 80 + x ) = 52%
\n" ); document.write( "( 32 + x ) / ( 80 + x ) = 0.52
\n" ); document.write( "32 + x = 0.52( 80 + x )
\n" ); document.write( "32 + x = 41.6 + 0.52x
\n" ); document.write( "0.48x = 9.6
\n" ); document.write( "x = 20 Litres of antifreeze
\n" ); document.write( "
\n" );