document.write( "Question 147618: eighty liters of a 40% antifreeze solution had to be strengthened so it contained 52% antifreeze. how much should be added? \n" ); document.write( "
Algebra.Com's Answer #107990 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! I'm guessing you are adding 100% or pure antifreeze. \n" ); document.write( "( 80 * 40% + x * 100% ) / ( 80 + x ) = 52% \n" ); document.write( "( 32 + x ) / ( 80 + x ) = 0.52 \n" ); document.write( "32 + x = 0.52( 80 + x ) \n" ); document.write( "32 + x = 41.6 + 0.52x \n" ); document.write( "0.48x = 9.6 \n" ); document.write( "x = 20 Litres of antifreeze \n" ); document.write( " |