document.write( "Question 147596: Graph \"y=sqrt%28x%2B3%29-3\" by using \"y=sqrt%28x%29\" \n" ); document.write( "
Algebra.Com's Answer #107965 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Start with the graph of \"y=sqrt%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%28x%29%29+\" Graph of \"y=sqrt%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now it turns out that if you generate a table for the equation of \"y=sqrt%28x%2B3%29\", then you'll see that the graph is shifted 3 units to the left like this\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%28x%29%2Csqrt%28x%2B3%29%29+\" Graph of \"y=sqrt%28x%29\" (red) and the new graph \"y=sqrt%28x%2B3%29\" (green) that has been shifted 3 units to the left.\r
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\n" ); document.write( "\n" ); document.write( "Now subtracting 3 from the entire equation gives you \"y=sqrt%28x%2B3%29-3\" which will shift the entire graph of \"y=sqrt%28x%2B3%29\" down 3 units.\r
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\n" ); document.write( "\n" ); document.write( "So we end up with \r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%28x%29%2Csqrt%28x%2B3%29-3%29+\" Graph of \"y=sqrt%28x%29\" (red) and the new graph \"y=sqrt%28x%2B3%29-3\" (green) that has been shifted 3 units to the left and 3 units down.
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