document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147558>Question 147558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm not quite sure how to simplify the expression 4 over 2+5i (4/2+5i) and I'm not quite sure what i to the -35th power means. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107944 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i^(-35)<BR>\n" );
document.write( "1/i^35<BR>\n" );
document.write( "1/( i * i^34 ) ~ you want an even power<BR>\n" );
document.write( "1/( i * (i^2)^17 ) ~ now, you want an exponent of 2<BR>\n" );
document.write( "1/( i * (-1)^17 ) ~ i^2 = -1<BR>\n" );
document.write( "-1 / i ~ (-1)^17 = -1\r<BR>\n" );
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document.write( "..\r<BR>\n" );
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document.write( "4 / (2 + 5i)<BR>\n" );
document.write( "4(2 - 5i) / (2 + 5i)(2 - 5i) ~ multiply the num. and dem. by the conjugate </SPAN>\n" );
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