document.write( "Question 147558: I'm not quite sure how to simplify the expression 4 over 2+5i (4/2+5i) and I'm not quite sure what i to the -35th power means. \n" ); document.write( "
Algebra.Com's Answer #107942 by stanbon(75887)\"\" \"About 
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I'm not quite sure how to simplify the expression 4 over 2+5i (4/2+5i) and I'm not quite sure what i to the -35th power means.
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\n" ); document.write( "4/(2+5i)
\n" ); document.write( "----
\n" ); document.write( "Multiply numerator and denominator by (2-5i) to get:
\n" ); document.write( "[4(2-5i)]/[4+25]
\n" ); document.write( "= (8-20i)/29
\n" ); document.write( "-----------------
\n" ); document.write( "i^(-35)
\n" ); document.write( "Applying the -1 exponent you get:
\n" ); document.write( "(i^3)^35
\n" ); document.write( "Applying the 35 exponent you get:
\n" ); document.write( "= i^105\r
\n" ); document.write( "\n" ); document.write( "= i^(104+1)\r
\n" ); document.write( "\n" ); document.write( "= i^(104) * i^1\r
\n" ); document.write( "\n" ); document.write( "= 1 * i^1\r
\n" ); document.write( "\n" ); document.write( "= i
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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