document.write( "Question 147558: I'm not quite sure how to simplify the expression 4 over 2+5i (4/2+5i) and I'm not quite sure what i to the -35th power means. \n" ); document.write( "
Algebra.Com's Answer #107942 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I'm not quite sure how to simplify the expression 4 over 2+5i (4/2+5i) and I'm not quite sure what i to the -35th power means. \n" ); document.write( "---------------------------- \n" ); document.write( "4/(2+5i) \n" ); document.write( "---- \n" ); document.write( "Multiply numerator and denominator by (2-5i) to get: \n" ); document.write( "[4(2-5i)]/[4+25] \n" ); document.write( "= (8-20i)/29 \n" ); document.write( "----------------- \n" ); document.write( "i^(-35) \n" ); document.write( "Applying the -1 exponent you get: \n" ); document.write( "(i^3)^35 \n" ); document.write( "Applying the 35 exponent you get: \n" ); document.write( "= i^105\r \n" ); document.write( "\n" ); document.write( "= i^(104+1)\r \n" ); document.write( "\n" ); document.write( "= i^(104) * i^1\r \n" ); document.write( "\n" ); document.write( "= 1 * i^1\r \n" ); document.write( "\n" ); document.write( "= i \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |