document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147510>Question 147510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular box is 1 inch more than twice the height of the box, and the width is 3 inches more than the height.  If the volume of the box is 126 cubic inches, find the dimensions of the box.  L=2x+1; H=x; W=x+3, V=126 cu. in. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107941 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2x+1)(x)(x+3)=126 __ 2x^3+7x^2+3x-126=0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "factors of 126 are 7, 3, 3, 2, 1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "factors of 2 are 2, 1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "testing factors shows 3 as a root of the equation, so x-3 is a factor\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(x-3)(2x^2+13x+42)=0 __ the discriminant of 2x^2+13x+42 is negative, so the other two roots are not real\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "so, x=3 and the dimensions are L=7, H=3, W=6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );