document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147541>Question 147541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 300 liters of a 76% antifreeze solution had to be reduced to a 20% solution. How many liters of antifreeze should be extracted? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107929 by </B><A HREF=/tutors/aboutme.mpl?userid=jojo14344><B>jojo14344(1513)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jojo14344><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ratio and Proportion amigo.<BR>\n" );
document.write( "let \"x\"= amount in liters <BR>\n" );
document.write( "so, (300/0.76) = (x/0.20)<BR>\n" );
document.write( "x=(300*0.20) / 0.76<BR>\n" );
document.write( "x=79 liters<BR>\n" );
document.write( "therefore <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=300-79+=+221+liters ALIGN=MIDDLE  ALT=\"300-79+=+221+liters\"   DISABLED_style= \"max-width:90%; height:auto;\" > to be <font color=\"red\">E</font>xtracted<BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );