document.write( "Question 147539This question is from textbook algebra
\n" ); document.write( ": It says to factor the problem. The problem is 4x^2+7x-2, the answer I got was 62(2x^2+6^2-1) I got it wrond though. Please help me Thank You=) \n" ); document.write( "
Algebra.Com's Answer #107910 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Looking at \"4x%5E2%2B7x-2\" we can see that the first term is \"4x%5E2\" and the last term is \"-2\" where the coefficients are 4 and -2 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 4 and the last coefficient -2 to get -8. Now what two numbers multiply to -8 and add to the middle coefficient 7? Let's list all of the factors of -8:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -8:\r
\n" ); document.write( "\n" ); document.write( "1,2,4,8\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -8\r
\n" ); document.write( "\n" ); document.write( "(1)*(-8)\r
\n" ); document.write( "\n" ); document.write( "(2)*(-4)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(8)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(4)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 7\r
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First NumberSecond NumberSum
1-81+(-8)=-7
2-42+(-4)=-2
-18-1+8=7
-24-2+4=2
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\n" ); document.write( "\n" ); document.write( "From this list we can see that -1 and 8 add up to 7 and multiply to -8\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"4x%5E2%2B7x-2\", replace \"7x\" with \"-1x%2B8x\" (notice \"-1x%2B8x\" adds up to \"7x\". So it is equivalent to \"7x\")\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2%2Bhighlight%28-1x%2B8x%29%2B-2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"4x%5E2-1x%2B8x-2\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%5E2-1x%29%2B%288x-2%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%284x-1%29%2B2%284x-1%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"2\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%284x-1%29\" Since we have a common term of \"4x-1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"4x%5E2-1x%2B8x-2\" factors to \"%28x%2B2%29%284x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"4x%5E2%2B7x-2\" factors to \"%28x%2B2%29%284x-1%29\" (since \"4x%5E2%2B7x-2\" is equivalent to \"4x%5E2-1x%2B8x-2\")\r
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\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"4x%5E2%2B7x-2\" factors to \"%28x%2B2%29%284x-1%29\"
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