document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147532>Question 147532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle is centered at the origin. The coordinates of one end point of a diameter are (3 + square root of 2, -4). What are the coordinates of the other endpoint of the diameter?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107900 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A circle is centered at the origin. The coordinates of one end point of a diameter are (3 + square root of 2, -4). What are the coordinates of the other endpoint of the diameter? <BR>\n" );
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document.write( "For every (x,y) on the circle, the diagonally opposite point is (-x,-y)<BR>\n" );
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document.write( "Your problem:<BR>\n" );
document.write( "Opposite of (3+sqrt(2),-4) is (-(3+sqrt(2)), 4)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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