document.write( "Question 147467: the length of a rectangle is 7 more than the width. the perimeter is 34 meters.\r
\n" ); document.write( "\n" ); document.write( "what is the width and length in meters and what is the area in square meters?\r
\n" ); document.write( "\n" ); document.write( "please help me please.... \n" ); document.write( "
Algebra.Com's Answer #107852 by nerdybill(7384)\"\" \"About 
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the length of a rectangle is 7 more than the width. the perimeter is 34 meters. what is the width and length in meters and what is the area in square meters?
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\n" ); document.write( "Let W = width of the rectangle
\n" ); document.write( "then from \"length of a rectangle is 7 more than the width\" we have
\n" ); document.write( "W+7 = length of the rectangle
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\n" ); document.write( "Remember the perimeter of any rectangle is:
\n" ); document.write( "L+L+W+W = 2(L+W)
\n" ); document.write( "And, because the perimeter is 34 meters we get:
\n" ); document.write( "34 = 2(L+W)
\n" ); document.write( "Earlier, we said that L=W+7 so plug that in and we get:
\n" ); document.write( "34 = 2(W+7+W)
\n" ); document.write( "34 = 2(2W+7)
\n" ); document.write( "34 = 4W+14
\n" ); document.write( "20 = 4W
\n" ); document.write( "5 meters = W (the width)
\n" ); document.write( "W+7 = 5+7= 12 meters (the length)
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\n" ); document.write( "Area = LW = 12(5) = 60 sq meters\r
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