document.write( "Question 147408: An airplane flew for 3 hours with a tail wind of 40 km/hr. The Return flight against the same wind took 4 hours. Find The Speed of the airplane in still air. \n" ); document.write( "
Algebra.Com's Answer #107841 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "SEEING AS THE DISTANCES ARE THE SAME WE HAVE: \n" ); document.write( "(R+40)3=(R-40)4 \n" ); document.write( "3R+120=4R-160 \n" ); document.write( "3R-4R=-160-120 \n" ); document.write( "-R=-280 \n" ); document.write( "R=280 KM/HR THE PLANES SPEED IN STILL AIR. \n" ); document.write( " \n" ); document.write( " |