document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147442>Question 147442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y=x^2-6x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107834 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107834\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I assume you want a graph. First, find the intercepts, then the vertex.\r<BR>\n" );
document.write( "\n" );
document.write( "x-intercepts:  0=x(x-6)  means x=0 or x=6<BR>\n" );
document.write( "y-intercepts y=0<BR>\n" );
document.write( "vertex will be -b/(2a) from form ax^2+bx+c=f(x). So x=3. This gives a corresponding y-value of y=9-18=-9. So (3,-9) is the vertex. \r<BR>\n" );
document.write( "\n" );
document.write( "This is all the information you need to produce the following:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-6x%29 ALIGN=MIDDLE  ALT=\"graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-6x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );