document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147421>Question 147421</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the perimeter of a figure if it shows you a variable  added to  the number one over four for the width, and a variable over 3 for the length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107791 by </B><A HREF=/tutors/aboutme.mpl?userid=aswathytony><B>aswathytony(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aswathytony><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since its not specified what figure is it , assume it as a rectangle.\r<BR>\n" );
document.write( "\n" );
document.write( "   given width  = x + 1/4\r<BR>\n" );
document.write( "\n" );
document.write( "    length = x/3 \r<BR>\n" );
document.write( "\n" );
document.write( "perimeter of rectangle = 2(l+ b)<BR>\n" );
document.write( "                      = 2 ( (x + 1/4 ) + x/3 )<BR>\n" );
document.write( "                      = 2 (  ( 4x + 1 )4  + x/3 )<BR>\n" );
document.write( "                      = 2 (   12x + 3 + 4x )/12<BR>\n" );
document.write( "                      = ( 12 x +  3 + 4x)/6<BR>\n" );
document.write( "                      = ( 16x + 3 )/6 <BR>\n" );
document.write( "                        </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );