document.write( "Question 147420: Three consecutive integers such that the sum of the first, twice the second and three times the third is 80. What are the integers? \n" ); document.write( "
Algebra.Com's Answer #107784 by nabla(475)\"\" \"About 
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integers:
\n" ); document.write( "a
\n" ); document.write( "a+1
\n" ); document.write( "a+2\r
\n" ); document.write( "\n" ); document.write( "Convert words to symbols:
\n" ); document.write( "a+2(a+1)+3(a+2)=80
\n" ); document.write( "6a+8=80
\n" ); document.write( "6a=72
\n" ); document.write( "a=12\r
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\n" ); document.write( "\n" ); document.write( "So the numbers are 12, 13, and 14.\r
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