document.write( "Question 147420: Three consecutive integers such that the sum of the first, twice the second and three times the third is 80. What are the integers? \n" ); document.write( "
Algebra.Com's Answer #107784 by nabla(475)![]() ![]() ![]() You can put this solution on YOUR website! integers: \n" ); document.write( "a \n" ); document.write( "a+1 \n" ); document.write( "a+2\r \n" ); document.write( "\n" ); document.write( "Convert words to symbols: \n" ); document.write( "a+2(a+1)+3(a+2)=80 \n" ); document.write( "6a+8=80 \n" ); document.write( "6a=72 \n" ); document.write( "a=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the numbers are 12, 13, and 14.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |