document.write( "Question 147416: A mother is 27 years older than her daughter. A year ago, the mother was twice as old as her daughter. how old is each now? \n" ); document.write( "

Algebra.Com's Answer #107782 by 24HoursTutor.com(40) $\"\"$ $\"About$

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Assume the present age of the mother to be x
\n" ); document.write( "Assume the present age of the daughter to be y\r
\n" ); document.write( "\n" ); document.write( "According to the information given at present the mother is 27 years elder than her daughter giving us the following equation :
\n" ); document.write( "x = 27 + y\r
\n" ); document.write( "\n" ); document.write( "Now, the scenario shifts to one previous year , so now :
\n" ); document.write( "age of mother = x-1
\n" ); document.write( "age of daughter=y-1
\n" ); document.write( "It is given that a year earlier the mother was twice the daughter's age, so we have the following equation:
\n" ); document.write( "x-1{age of mother an year ago}=2(y-1) {age of daughter one year ago}
\n" ); document.write( "x-1=2y-2
\n" ); document.write( "x=2y-2+1
\n" ); document.write( "x=2y-1\r
\n" ); document.write( "\n" ); document.write( "Now substituting it in our previous equation we get :
\n" ); document.write( "2y-1=27+y
\n" ); document.write( "2y-y=27+1
\n" ); document.write( "y=28
\n" ); document.write( "x+=27+y=27+28=55\r
\n" ); document.write( "\n" ); document.write( "Ans: Age of mother = x = 55
\n" ); document.write( " Age of daughter = y = 28
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