document.write( "Question 147399: The current was 3 mph. The fast boat could go 92 miles downstream in the same time it took to go 68 miles upstream. How lond did each trip take and what was the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #107774 by stanbon(75887)\"\" \"About 
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The current was 3 mph. The fast boat could go 92 miles downstream in the same time it took to go 68 miles upstream. How lond did each trip take and what was the speed of the boat in still water?
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\n" ); document.write( "Let the boat speed in still water be \"b\".
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance = 92 miles ; rate = b+3 mph ; time = d/r = 92/(b+3) hrs.
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "disance = 68 miles ; rate = b-3 mph ; time = d/r = 68/(b-3) hrs.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "time up = time down
\n" ); document.write( "68/(b-3) = 92/(b+3)
\n" ); document.write( "68b+204 = 92b-276
\n" ); document.write( "24b = 480
\n" ); document.write( "b = 20 mph (speed of the boat in still water)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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