document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147375>Question 147375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fishing boat traveled 3 hours against a 6 km/hr current. The return trip took only 2 hours. Find the speed of the boat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107751 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A fishing boat traveled 3 hours against a 6 km/hr current. The return trip took only 2 hours. Find the speed of the boat in still water.<BR>\n" );
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document.write( "Against current DATA:<BR>\n" );
document.write( "Time = 3 hrs ; rate = b-6 : distance = tr = 3(b-6) = 3b-18 km<BR>\n" );
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document.write( "With current DATA:<BR>\n" );
document.write( "Time = 2 hrs ; rate = b+6 ; distance = tr = 2(b+6) = 2b+12 km<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "distance with = distance against<BR>\n" );
document.write( "2b+12 = 3b-18<BR>\n" );
document.write( "b = 30 kph (speed of the boat in quiet water)<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );