document.write( "Question 147379: I'm attempting to help my child with an absolute value problem that she cannot solve and it has been a long time since I have had Algebra. Help please! Please show work with explanation and then I will work it through with her not providing the answer directly. Thanks!\r
\n" ); document.write( "\n" ); document.write( "Find the absolute value inequality for the following:\r
\n" ); document.write( "\n" ); document.write( "x < 6 or x > 11
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Algebra.Com's Answer #107750 by nabla(475)\"\" \"About 
You can put this solution on YOUR website!
Essentially what we want here is
\n" ); document.write( "x < 6 or x > 11\r
\n" ); document.write( "\n" ); document.write( "Look at the endpoints. 6 and 11 are 5 units apart. Half of 5 is 2.5. So you want to adjust the inequality so it relates to –2.5 and 2.5 INSTEAD of 6 and 11. You will need to subtract 8.5 all around.\r
\n" ); document.write( "\n" ); document.write( "x-8.5 < 6-8.5 or x-8.5 > 11-8.5
\n" ); document.write( "x-8.5 < -2.5 or x-8.5 > 2.5\r
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\n" ); document.write( "\n" ); document.write( "Now, recall GOLA. This is a simple rule that says if the absolute valued terms are greater, we will use OR. If the absolute valued terms are less, we will use and.
\n" ); document.write( "Since this is the \"greater than\" format (use of or), the absolute-value inequality will be of the form \"absolute value of something is greater than 2.5\". You can convert this nicely to\r
\n" ); document.write( "\n" ); document.write( "|x-8.5| > 2.5
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