document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22215>Question 22215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A FIELD SHAPE LIKE A TRIANGLE HAS A PRIMETER OF 224 METERS.THE LENGTH OF THE SECOND SIDE IS TWICE THE LENGTH OF THE FIRST SIDE,AND THE THIRD SIDE IS HALF THE LENGTH OF THE FIRST SIDE.FIND THE LENGTHS OF THE THREE SIDES. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10775 by </B><A HREF=/tutors/aboutme.mpl?userid=SuperGirl98734><B>SuperGirl98734(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=SuperGirl98734><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if...<BR>\n" );
document.write( "frist side = a<BR>\n" );
document.write( "second side = 2a<BR>\n" );
document.write( "third side = a/2<BR>\n" );
document.write( "then...<BR>\n" );
document.write( "a+2a+a/2=224<BR>\n" );
document.write( "3a+a/2=224<BR>\n" );
document.write( "(2)3a+a/2=224(2)<BR>\n" );
document.write( "6a+a=448<BR>\n" );
document.write( "7a=448<BR>\n" );
document.write( "a=64<BR>\n" );
document.write( "so...<BR>\n" );
document.write( "first side = 64<BR>\n" );
document.write( "second side = 128<BR>\n" );
document.write( "third side = 32\r<BR>\n" );
document.write( "\n" );
document.write( "i hope that helped and wasnt too hard to understand :) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );