document.write( "Question 147362: Factor; 4a^2-4a+1
\n" ); document.write( "I did it just like by this problem; a^2-9= a^2-3^2= (a+3)(a-3, but it was wrong.
\n" ); document.write( "

Algebra.Com's Answer #107734 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "Looking at \"4a%5E2-4a%2B1\" we can see that the first term is \"4a%5E2\" and the last term is \"1\" where the coefficients are 4 and 1 respectively.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 4 and the last coefficient 1 to get 4. Now what two numbers multiply to 4 and add to the middle coefficient -4? Let's list all of the factors of 4:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Factors of 4:\r
\n" ); document.write( "\n" ); document.write( "1,2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-1,-2 ...List the negative factors as well. This will allow us to find all possible combinations\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 4\r
\n" ); document.write( "\n" ); document.write( "1*4\r
\n" ); document.write( "\n" ); document.write( "2*2\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-4)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(-2)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to -4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
First NumberSecond NumberSum
141+4=5
222+2=4
-1-4-1+(-4)=-5
-2-2-2+(-2)=-4
\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "From this list we can see that -2 and -2 add up to -4 and multiply to 4\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"4a%5E2-4a%2B1\", replace \"-4a\" with \"-2a%2B-2a\" (notice \"-2a%2B-2a\" adds up to \"-4a\". So it is equivalent to \"-4a\")\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4a%5E2%2Bhighlight%28-2a%2B-2a%29%2B1\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's factor \"4a%5E2-2a-2a%2B1\" by grouping:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%284a%5E2-2a%29%2B%28-2a%2B1%29\" Group like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2a%282a-1%29-1%282a-1%29\" Factor out the GCF of \"2a\" out of the first group. Factor out the GCF of \"-1\" out of the second group\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282a-1%29%282a-1%29\" Since we have a common term of \"2a-1\", we can combine like terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"4a%5E2-2a-2a%2B1\" factors to \"%282a-1%29%282a-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So this also means that \"4a%5E2-4a%2B1\" factors to \"%282a-1%29%282a-1%29\" (since \"4a%5E2-4a%2B1\" is equivalent to \"4a%5E2-2a-2a%2B1\")\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "note: \"%282a-1%29%282a-1%29\" is equivalent to \"%282a-1%29%5E2\" since the term \"2a-1\" occurs twice. So \"4a%5E2-4a%2B1\" also factors to \"%282a-1%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"4a%5E2-4a%2B1\" factors to \"%282a-1%29%5E2\"
\n" ); document.write( "
\n" ); document.write( "
\n" );