document.write( "Question 147347This question is from textbook Elementary and Intermediate Algebra
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document.write( ": Find b^2 - 4ac and the number of real solutions:\r
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document.write( "4m^2 + 25 = 20m\r
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document.write( "The book shows an answer of (0, 1)\r
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document.write( "I have tried to work it by changing to a quadratic and using the discriminant to figure the answer, but I end up with m = 5/2\r
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document.write( "I would greatly appreciate if someone can tell me how to work this problem. I am completely stumped. Thanks! \n" );
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Algebra.Com's Answer #107725 by nabla(475)![]() ![]() ![]() You can put this solution on YOUR website! Rewrite as\r \n" ); document.write( "\n" ); document.write( "4m^2-20m+25=0\r \n" ); document.write( "\n" ); document.write( "where \n" ); document.write( "am^2+bm+c=0 is the form we're interested in.\r \n" ); document.write( "\n" ); document.write( "so \n" ); document.write( "b^2-4ac=(-20)^2-4*4*25=400-400=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the discriminant is 0 we shall have 1 solution. You can see why this is so from the quadratic formula: \n" ); document.write( " \n" ); document.write( "If we eliminate the root due to a zero, the +/- is irrelevant and leaves only -b/2a as the solution of x.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |