document.write( "Question 147349: Kelly is two years yonger than Kristen. If twice Kristen's age is increased by five times Kelly's age the sum is 53. Find the ages of the two girls. I came up wiht Kristen 8.14 and Kelly 6.14.......that is two years less, but it doesn't work. \n" ); document.write( "

Algebra.Com's Answer #107724 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Let x=Kristen's age; 2x =twice Kristen's age
\n" ); document.write( "Then x-2=Kelly's age; 5(x-2)=5 times Kelly's age\r
\n" ); document.write( "\n" ); document.write( "2x+5(x-2)=twice Kristen's age increased by 5 times Kelly's age and we are told this equals 53. So our equation to solve:\r
\n" ); document.write( "\n" ); document.write( "2x+5(x-2)=53 get rid of parens (distributive law)
\n" ); document.write( "2x+5x-10=53 add 10 to each side\r
\n" ); document.write( "\n" ); document.write( "2x+5x-10+10=53+10 collect like terms\r
\n" ); document.write( "\n" ); document.write( "7x=63 divide each side by 7\r
\n" ); document.write( "\n" ); document.write( "x=9----------------------Kristen's age
\n" ); document.write( "x-2=9-2=7--------------Kelly's age\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "2*9+5*7=53
\n" ); document.write( "18+35=53
\n" ); document.write( "53=53\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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