document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147332>Question 147332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is fixed at 15cm. what widths will make the peramiter greater than 76cm? the width must be greater than __ cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107710 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter is:<BR>\n" );
document.write( "L+L+W+W<BR>\n" );
document.write( "or<BR>\n" );
document.write( "2L+2W<BR>\n" );
document.write( "or<BR>\n" );
document.write( "2(L+W)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Since the problem fixed L as 15 cm AND the perimeter as greater than 76 we get our equation:<BR>\n" );
document.write( "2(15+W) > 76<BR>\n" );
document.write( "30 + 2W > 76<BR>\n" );
document.write( "2W > 46<BR>\n" );
document.write( "W > 23 cm<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );