document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147328>Question 147328</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780395977224/algebrahomeworkh>algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Ok, with this particular question I did it again and again, but my answer just doesn't add up. This is Transforming equations...Again. The problem is <BR>\n" );
document.write( "3(x-5)+7=16, and I got 3x=38<BR>\n" );
document.write( "The way I solved it was this way: 3(x-5)+7=16  3x-15+7=16  3x-22=16  3x-22+22=16+22 which equals to 3x=38, but I have the feeling it's wrong. Please help me, thank you=) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107699 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(x-5)+7=16<BR>\n" );
document.write( "3(x-5) = 9<BR>\n" );
document.write( "x-5 = 3 <BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );