document.write( "Question 147306: can you please solve the equation:2x (3+4x)-4x(3-6x)is greater or less than10.
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Algebra.Com's Answer #107681 by checkley77(12844)\"\" \"About 
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2x(3+4x)-4x(3-6x)>=10
\n" ); document.write( "6x+8x^2-12x+24x^2-10>=0
\n" ); document.write( "32x^2-6x-10>=0
\n" ); document.write( "2(16x^2-3x-5)>=0
\n" ); document.write( "using the quadratic equation: \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" we get:
\n" ); document.write( "x=(3+-sqrt[-3^2-4*16*-5])/2*16
\n" ); document.write( "x=(3+-sqrt[9+320])/32
\n" ); document.write( "x=(3+-sqrt329)/32
\n" ); document.write( "x=(3+-18.14)/32
\n" ); document.write( "x=(3+18.14)/32
\n" ); document.write( "x=21.14/32
\n" ); document.write( "x=.66 answer.
\n" ); document.write( "x=(3-18.14)/32
\n" ); document.write( "x=-15.14/32
\n" ); document.write( "x=-.473 answer. \r
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